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Taschenbuch der Mathematik
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匹配长序列文本:
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a) a~pq=1apq .(18.16a)
b) a~pj=apj⋅a~pq,j≠q,b~p=bp⋅a~pq .(18.16b)
c) a~iq=−aiq⋅a~pq,i≠p,c~q=−cq⋅a~pq .(18.16c)
d) a~ij=aij+apj⋅a~iq,i≠p,j≠q ,
b~i=bi+bp⋅a~iq,i≠p,
c~j=cj+apj⋅c~q,j≠q,−c~0=−c0+bp⋅c~q. (18.16d)